In figure abcd is a trapezium of area 24.5
WebABCD is trapezium of area 24.5 sq.cm.in it AD BC angle DAB=90 degree AD=10cm and BC =4cm. If ABE is a quadrant of a circlefind the area of the shaded region. …WebMar 15, 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto …
In figure abcd is a trapezium of area 24.5
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WebJan 12, 2024 · Solution For 4. In figure, ABCD is a trapezium of area 24.5 sq. cm. in it, AD∥BC,∠DAV=90∘,AD =10 cm and BC=4 cm. if ABE is a quadrant of a circle, find the area ... WebIn figure, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC, ∠ DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region 2. In figure, ABDC is a quadrant of a circle of radius 28 cm and a semicircle BEC is drawn with BC as diameter. Find B the area of the shaded region. 3.
</dab>WebIn Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC, ∠ DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. Take π= 227 from Mathematics Areas Related to Circles Class 10 Punjab Board Mathematics Mathematics Download books and chapters from book store.
WebABCD is trapezium of area 24.5 sq.cm.in it AD BC angle DAB=90 degree AD=10cm and BC =4cm. If ABE is a quadrant of a circlefind the area of the shaded region. AboutPressCopyrightContact... WebDec 23, 2024 · We know the area of trapezium= 1/2× ( sum of parallel sides)× height so, 24.5= 1/2× (10+4)×h h= 49/14 cm= 3.5cm now, the area of circular part (ie. AEB)= 1/4 × 22/7 × 3.5×3.5 = 8.625cm^2 so, area of shaded region= 24.5 - 8.625=15.875 sq cm wrong sum Advertisement Lokeshaswale8281 The answer is added to the attachment below …
WebThe figure according to the question is shown below. Now first observe the figure carefully and then look at the solution. A s w e k n o w t h a t a r e a o f t r a p e z i u m = 1 2 × ( s u m o f p a r a l l e l s i d e s ) × d i s tan c e b e t w e e n t h e p a r a l l e l s i d e s H e n c e a c c o r d i n g t o t h e f i g u r e a r e a ...
WebMar 3, 2014 · Area of the trapezium = h/2 (a + b) where a and b are the parallel sides and h is the perpendicualr distance between the parallel sides. Area of the trapezium ABCD = AB/2 … fébuxostat vidalWebApr 4, 2024 · Area of the trapezium is 24.5 sq.cm. We know that the area of the trapezium is half of the sum of parallel sides multiplied by perpendicular distance between them. i.e. … feb vatWebAnswer this please Q In figure ABCD is a trapezium of area 24 5 sq cm In it, AD ∥ BC, ∠DAB=90 , AD = 10 cm and BC = 4 cm If ABE is a quadrant of a circle, find ...febzedWeb24. In figure 3, ABCD is a trapezium of area 24.5 sq. cm. In it, AD BC, ∠DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. …hotel atlas amadil agadirWebMar 15, 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get … feb vanity fair magazine 2018febvotteWebGiven Area of trapezium ABCD = 24.5 cm2→ eqn1. AD ∥ BC, AD = 10 cm, BC = 4 cm, ∠DAB = 90°. Putting the values in equation 2, we get, ⇒ AB = 3.5 cm. Therefore radius of the …febyst-sz